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The velocity of an electron in a certain Bohr orbit of H-atom beaes the ratio 1 : 275 to the velocity of light. The quantum number (n) of the orbit isA. 3B. 2C. 1D. 4 |
Answer» Correct Answer - B Velocity of electrons = `1/275xx " velocity of light " 1/275xx3xx10^(10)=1.09xx10^(8)cms^(-1)` Since `v_(n)=(2pie^(2))/(nh)` `therefore " " 1.09xx10^(8)=(2xx3.14xx(4.803xx10^(-10))^(2))/(6.626xx10^(-27)xxn)` ` therefore " "n=2` |
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