The velocity of an electron in excited state of H-atom is 1.093 xx 10^6 m/s, what is the circumference of this orbit?

The velocity of an electron in excited state of H-atom is 1.093 xx 10^

1.	The velocity of an electron in excited state of H-atom is 1.093 xx 10^6 m/s, what is the circumference of this orbit?
Answer» `3.32 xx10^(-10)` m `6.64 XX 10^(-10) `m `13.30xx10^(-10)` `13.28xx10^(-8) m` Solution :`v_n = 2.186 xx 10^6Z/n ` m/sec `implies1.093 xx 10^6 = 2.186 xx 10^6 xx 1/n = 2 ` CIRCUMFERENCE of the ORBIT = 3.33 `xx n^2 A^0`