The velocity of e^(-) in a certain Bohr orbitof the hydrogen atom bears the ratio 1:275 to the velocity of light. What is the quantum no. "n" of the orbit and the wave no. of the radiation emitted for the transition form the quantum state (n+1) to the ground state.

The velocity of e^(-) in a certain Bohr orbitof the hydrogen atom bear

1.	The velocity of e^(-) in a certain Bohr orbitof the hydrogen atom bears the ratio 1:275 to the velocity of light. What is the quantum no. "n" of the orbit and the wave no. of the radiation emitted for the transition form the quantum state (n+1) to the ground state.
Answer» Solution :`V_(n)=2.18xx10^(6)xx(Z)/(n)=(2.18xx10^(6))/(n)` `(2.18xx10^(6))/(n)=(1)/(275)` `(2.18xx10^(6))/(n)=(1)/(3XX10^(8))=(1)/(275)` `(2.18)/(n(300))=(1)/(275)""(1)/(n)=(300)/(599.5)` `n=(599.5)/(300)=(1)/(275)""(1)/(n)=(300)/(599.5)` `n=1.99~=2`