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The velocity of electromagnetic radiatior in a medium of permittivity `epsilon_(0)` and permeability `mu_(0)` is given byA. `sqrt((epsilon_(0))/(mu_(0)))`B. `sqrt(mu_(0)epsilon_(0))`C. `(1)/(sqrt(mu_(0)epsilon_(0)))`D. `sqrt((mu_(0))/(epsilon_(0)))` |
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Answer» Correct Answer - C Velocity of electromagnetic radiation is the velocity of light (c), is `(1)/(sqrt(mu_(0)epsilon_(0)))` Where `mu_(0)` is the permeability and `epsilon_(0)` is the permittivity of free space. |
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