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The velocity of electromagnetic radiatior in a medium of permittivity `epsilon_(0)` and permeability `mu_(0)` is given byA. `sqrt(mu//E)`B. `sqrt(muepsi)`C. `1//sqrt(muepsi)`D. `sqrt(epsi//mu)` |
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Answer» Correct Answer - C For a medium with permittivity `epsi` and permeability `mu`, velocity of light is given by `c = (1)/(sqrt(muepsi))` |
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