1.

The velocity of electromagnetic radiatior in a medium of permittivity `epsilon_(0)` and permeability `mu_(0)` is given byA. `(1)/(sqrt(mu_(0)K_(0))`B. `(1)/(mu_(0)K_(0))`C. `sqrt(mu_(0)K_(0))`D. `mu_(0)K_(0)`

Answer» Correct Answer - c
`mu=(c)/(v)`
Now `c=(1)/(sqrt(mu_(0)inK_(0)))` and `v=(1)/(sqrt(mu_(0)K_(0)mu_(r)K_(r)))`
`:. mu=sqrt(mu_(r)K_(r))`
But `mu_(r)=u_(0)` and `K_(r)=K_(0)`
`:.mu=sqrt(mu_(0)K_(0))`


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