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The velocity of the particle midway between mean and extreme position, performing S.H.M. isA. `A omega`B. `(sqrt(3))/(2)A omega`C. `(2)/(sqrt(2))A omega`D. `sqrt(3)A omega` |
Answer» Correct Answer - B `v_(m)=omegasqrt(A^(2)-x^(2))=omegasqrt(A^(2)-(A^(2))/(4))` `=omegasqrt((4A^(2)-A^(2))/(4)` `=omegasqrt((3A^(2))/(4))=sqrt(3)/(2)Aomega` |
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