1.

The velocity ofa river current is u. A man crosses the river with velocity v making an angle theta with thedirection of the current. If the width of the river is d, find the time taken to cross the river and the displacement of the man in the direction of the current. What would be the minimum time required for crossing the river ?In what time could he reach exactly the opposite point ?

Answer»


ANSWER :`d/(VSIN THETA);DCOT theta;d/(SQRT(u^2+v^2-2uvcos theta));d/(sqrt(v^2-2uvcos theta))`


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