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The velocity vector of a body is given by `vec(v)=2hati+(3-6t)hatj m//s`. At the initial moment the body is at origin. Find x-coordinate (in m) at the time when its y-coordinate is maximum. |
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Answer» Correct Answer - 1 `vec(v) =2hati+(3-6t)hatj` x=2t+C`" " `[t=0,x=0] `rArr x=2t......(i)` `y=3t-3t^(2)+C` `y=3t-3t^(2)......(ii)` Put `t=x/2` inequation (2) `y=(3x)/2 3(x/2)^(2)` `y=(3x)/2-(3x^(2))/4` `y=3/2(x-(x^(2))/2)` For `y_(max)` `(dy)/(dx)=0` `(dy)/(dx)=3/2 (1-x)=0 " " rArr x=1m` |
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