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The velocityof a particle that moves in the positive X- direction varies with its position, as shown in figure-1.22. Find its acceleration in `m//s^(2)` where `x = 6m` A. `- 1.5 m//s^(2)`B. `1.5 m//s^(2)`C. `2 m//s^(2)`D. `-2 m//s^(2)` |
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Answer» Correct Answer - A `a = (vdv)/(dx) = 3 (-(1)/(2)) = -1.5 m//s^(2)` |
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