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The velovity-time graph of a particle moving in a straitht line is shown in . The acceleration of the particle at `t=9 s` is. .A. ZeroB. `5 m s^(-2)`C. `-5 m s^(-2)`D. `-2 m s^(2)` |
Answer» Correct Answer - C Acceleration between `8` and `10 s or at `t=9 s`: `a= (v_(2)-v_(1))/(t_(2) -t_(1)) =(5-15)/(10-8) =- ms^(-2)`. |
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