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The vernier constant of Vernier callipers is 0.1 mm and it has zero error of (-0.05) cm. While measuring diameter of a sphere, the main scale reading is 1.7 cm and coinciding vernier division is 5. The corrected diameter will be_____ x 10-2 cm. |
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Answer» Correct answer is 180 Measured diameter = MSR + VSR × VC = 1.7 + 0.01 × 5 = 1.75 Corrected = Measured – Error = 1.75 – (–0.05) = 1.80 cm = 180 x 10–2 cm 180 |
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