1.

The vernier constant of Vernier callipers is 0.1 mm and it has zero error of (-0.05) cm. While measuring diameter of a sphere, the main scale reading is 1.7 cm and coinciding vernier division is 5. The corrected diameter will be_____ x 10-2 cm.

Answer»

Correct answer is 180

Measured diameter = MSR + VSR × VC 

= 1.7 + 0.01 × 5 = 1.75

Corrected = Measured – Error 

= 1.75 – (–0.05) 

= 1.80 cm 

= 180 x 10–2 cm 

180



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