1.

The vertex A of a triangle lies on the lines x+y=1 and 2x+3y=6 . If the orthocentre of the triangle is O ((3)/(7),(22)/(7)) then the equation of OA in the normal form is

Answer»

x cos`alpha+ysinalpha=7, alpha=tan^(-1)(1)/(7)`
`x cos alpha+ysin alpha = (13)/(SQRT(17)), alpha= tan^(-1)((1)/(4))`
`XCOS alpha + ysin alpha = (13)/(4), alpha = tan^(-1) ((13)/(sqrt(17)))`
`x cos alpha+ysin alpha= (13)/(sqrt(17)), alpha = tan^(-1)(4)`

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