The vertical extension in a light spring by a weight of 1 kg, in equilibrium is 9.8 cm. The period of oscillation of the spring, in seconds, will be…………….

The vertical extension in a light spring by a weight of 1 kg, in equil

1.	The vertical extension in a light spring by a weight of 1 kg, in equilibrium is 9.8 cm. The period of oscillation of the spring, in seconds, will be…………….
Answer» `(2PI)/(10)` `(2pi)/(100)` `20pi` `200PI` SOLUTION :`T=2pisqrt((l)/(g))=2pisqrt((9.8xx10^(-2))/(9.8))=(2pi)/(10)s`