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The vertical extension in a light spring by a weight of 1 kg, in equilibrium is 9.8 cm. The period of oscillation of the spring, in seconds, will be…………….

Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>)`<br/>`(2pi)/(100)`<br/>`20pi`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/200pi-1820161" style="font-weight:bold;" target="_blank" title="Click to know more about 200PI">200PI</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`T=2pisqrt((l)/(g))=2pisqrt((9.8xx10^(-2))/(9.8))=(2pi)/(10)s`</body></html>


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