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The vertical height of the projectile at time t is given by y=4t−5t2 and the horizontal distance covered is given by x=3t where x and y are in m and t in s. What is the angle of projection with the horizontal? |
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Answer» The vertical height of the projectile at time t is given by y=4t−5t2 and the horizontal distance covered is given by x=3t where x and y are in m and t in s. What is the angle of projection with the horizontal? |
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