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InterviewSolution
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The vertical motion of a huge piston in a machine is approximately simple harmonic with a frequency of \(0.50\,s^{-1}.\) A block of 20 kg is placed on the piston. The maximum amplitude of the piston’s SHM, for the block and the piston to remains together is(a) 0.99 m(b) 1 m(c) 1.99 m(d) 2.8 m |
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Answer» Answer is : (a) 0.99 m The maximum acceleration for SHM is given by \(a_{max}=\omega^2A=(2\pi \upsilon)^2\) \(A=4\pi^2\upsilon^2A\) The block will remains in contact with the piston, if \(a_{max} \leq g\,or\) \(4\pi^2\upsilon^2A<g\) ∴ Maximum amplitude of piston will be \(A_{max}=\frac{g}{4\pi^2\upsilon^2}\) \(=\frac{9.8}{4\pi^2(0.5)^2}\) = 0.99 m |
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