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| 1. |
The Vividh Bharati station of All India Radio, Delhi, broadcasts on a frequency of 1,368 kHz (kilo hertz). Calculate the wavelength of the electromagnetic radiation emitted by transmitter. Which part of the electromagnetic spectrum does it belong to? |
| Answer» Solution :The wavelength, `lambda`, is equal to C/V, where c is the speed of electromagnetic radiation in vacuum and V is the frequency. Substituting the GIVEN VALUES, we have `V=c/V=(3.00xx10^8ms^(-1))/(1368 kHz)=(3.00xx10^8ms^-1)/(1368xx10^3s^(-1))=219.3m`It belongs to the radiowave region. | |