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the vividh bharati station of All india Radio, Delhi , broadcasts on a frequency of 1,368 kHz (kilo hertz). Calculate the wavelength of the electromagnetic radiation emitted by transmitter . Which part of the electromagnetic spectrum does it belong to |
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Answer» Solution :Wavelength, `lamda = (C)/(v)` Substituting `= c = 3 XX 10^(8) ms^(-1) and v = 1368 kHz` (Given) `= 1368 xx 10^(3) "CYCLES" s^(-1) "" (1 kHz = 10^(3) " cycles " s^(-1))` `= 1368 xx 10^(3) s^(-1)` We have, `lamda = (3 xx 10^(8) ms^(-1))/(1368 xx 10^(3) s^(-1)) = 219.3m` It belongs to the RADIOWAVE region of the electromagnetic spectrum. |
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