1.

The vividhBharati stationof All indiaRadioDelhi. Broadcastson a frequency of 1.368kHz(kilohertz)Calculatethe wavelengthofthe elctromagneticradiationemittedbytransmitter .Whichpartof theelectromagneticspectrum does itbelong to ?

Answer»

Solution :`C= v lambda`
`gamma= (c )/( v )`
`= 2193m`
WHEREC= speedof electron
magneticradiation
`=-3.0 xx 1 0^(8)ms^(-1)`
v= FREQUENCY= 1368kH z
=1368 `xx 10^(3) HZ`
`1368 xx 10^(3)s^(-1)`
this is acharacteristicradiowavewavelength.


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