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The vividhBharati stationof All indiaRadioDelhi. Broadcastson a frequency of 1.368kHz(kilohertz)Calculatethe wavelengthofthe elctromagneticradiationemittedbytransmitter .Whichpartof theelectromagneticspectrum does itbelong to ? |
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Answer» Solution :`C= v lambda` `gamma= (c )/( v )` `= 2193m` WHEREC= speedof electron magneticradiation `=-3.0 xx 1 0^(8)ms^(-1)` v= FREQUENCY= 1368kH z =1368 `xx 10^(3) HZ` `1368 xx 10^(3)s^(-1)` this is acharacteristicradiowavewavelength. |
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