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The vol. of o2 at stp required for the complete combustion of 4g CH4 is |
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Answer» 1/4 mole of CH4 will requires = 1/4 ×2 moles of O2 = 0.5 MOL of O2 for COMPLETE combustion. So 11.2 L of O2 is required for complete combustion of 4 G CH4. |
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