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The voltage drop across a standard resistor of 0.2 Ω is balanced at 83 cm. Find the magnitude of the current, if the standard cell emf of 1.53 V is balanced at 42 m.(a) 13.04 A(b) 10 A(c) 14.95 A(d) 12.56 AI have been asked this question by my college director while I was bunking the class.My question comes from Advanced Problems on Measurement of Low Medium and High Resistance in division Measurement of Resistance of Electrical Measurements

Answer»

Right option is (c) 14.95 A

To elaborate: Voltage drop per unit length = \(\frac{1.53}{42}\) = 0.036 V/CM

Voltage drop across 83 cm length = 0.036 × 83 = 2.99 V

∴ Current through resistor, I = \(\frac{2.99}{0.2}\) = 14.95 A.



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