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The volume in litres of `CO_(2)` liberated at STP when 10 grams of 90% pure limestone is heated cmpletely isA. `22.4`B. `2.24`C. `20.6`D. `2.016` |
Answer» Correct Answer - D Sample of limestone is only 90 % pure. Therefore, 100 g limestone sample contains 90 g pure `:.` 10 g limestone sample will contain `(10xx90)/(100)` `9.00 g` pure As limestone is nothing but `CaCO_(3)` `:.` 10 g limestone sample will contain `(10xx90)/(100) = 9.00` g pure As limestone is nothing but `CaCO_(3)` `:.` The molecular mass of `CaCO_(3) = 100` 100 g of limestone gives 22.4 litre of `CO_(2)` at S.T.P. `:.` 9 g of limestone will give `(22.4xx9)/(100) = 2.016` litre at S.T.P. Hence, 10g impure sample will give 2.016 litre of `CO_(2)` at STP |
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