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The volume (in mL) of 0.1 M AgNO_(3) required to completely precipitat the chloride ions present in 30 mL of 0.01 M of [Cr(H_(2)O)_(5)Cl]Cl_(2), as silver chloride is close to : |
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Answer» `(M_(1)V_(1))/(n_(1))=(M_(2)V_(2))/(n_(2))` `(0.1xxV)/(2)=(0.01xx30)/(1)` V=6 mL |
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