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The volume occupied by 0.32 g of a gas at S.T.R is 224 mL. Calculate the molecular mass of the gas. |
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Answer» SOLUTION :`therefore` 224 mL of the gas at S.T.P WEIGH = 0.32 G `therefore 22400 mL` of the gas at S.T.P. will weigh `=0.32/224 xx 22400 = 32 g` HENCE, the molecular mass of the gas = 32 amu |
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