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The volume occupied by 4.4 g of `CO_(2)` at STP isA. `2.4 L`B. `2.24 L`C. `44 L`D. `22.4 L` |
Answer» Correct Answer - B `n_(CO_(2)) = ("Mass"_(CO_(2)))/("Molar mass"_(CO_(2))) = (4.4 g)/(44 g "mol"^(-1)) = 0.1 "mol"` Under `STP` conditions , `n_(CO_(2)) = (V_(CO_(2)) "inliters at STP")/(22.4 L" mol"^(-1))` `0.1 "mol" = (V_(CO_(2)) "inliters at STP")/(22.4 L mol^(-1))` or `V_(CO_(2)) = (0.1 "mol") (22.4 L "mol"^(-1))` `= 2.24 L` |
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