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The volume of 0.1 M AgNO_(3) should be added to 10.0 ml of 0.09 M K_(2)CrO_(4) to precipitate all the chromate as Ag_(2)CrO_(4) is |
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Answer» Solution :eq. `AgNO_(3)` = eq. `K_(2)CrO_(4)` `0.1xx1xxV_(mL)=10xx0.09xx2impliesV_(mL)=18mL` |
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