1.

The volume of 0.1 M Ca(OH)_2required toneutralize 10 mL of 0.1 N HCI

Answer»

10 mL
20 mL
5ML
15mL

Solution :`0.1 M Ca(OH)_2 = 0.2 N Ca (OH)_2`
APPLYING `N_1V_1 = N_2V_2`
`0.2 XX V_1 = 0.1 xx 10`
` V_1 = (0.1 xx 10)/(0.2) =5mL`


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