1.

The volume of 0.1 M NaOH solution required to neutralise the solution produced by dissolving 1.1 g of P_4 O_6 in water is Y xx 100 . What is the value of Y ?

Answer»

Solution :`P_(4)O_(6)+6H_(2)O RARR 4H_(3)PO_3`
`(1.1gm)/(220)5xx10^3molrarr4xx5xx10^(-3)mol=2xx10^(-2)` mol
`H_(3)PO_(3)+2NaOHrarrNa_(2)HPO_3+2H_(2)O`
`2 xx 10 - 2mol 2 xx 2 xx 10^(-2) mol :. " moles of "NaOH = 4 xx10^(-2)=M_(NaOH)xxV_(LN2)`
`impliesV=(4xx10^(-2))/(M_(NaOH))=(4xx10^(-2))/(0.1)=0.4 ` LITER `implies V=400 ml = 4 xx 100 implies Y = 4`


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