1.

The volume of 0.1 M oxalic acid that can be completely oxidized by 20 mL of 0.025 M KMnO_4 solution is

Answer»

125mL
25mL
12.5mL
37.5 mL

Solution :`5H_2C_2O_4 + 2KMnO_4 + 3H_2SO_4 to 2MnSO_4 + K_2SO_4 + 10CO_2 + 8H_2O`
According to molarity EQUATION
` ( (M_1V_1)/(n_1) )_(KMnO_4) = ( (M_2V_2)/(n_2) )_("OXALIC ACID")`
or` (0.025 xx 20)/(2) = (0.1 xx V_2)/(5) `
`V_2 = (5 xx 0.025 xx 20)/(2 xx 0.1)`
`= 12.5 mL`


Discussion

No Comment Found

Related InterviewSolutions