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The volume of 0.1 MH SO, solution required to neutralize 50ml of 0.2M NaoH solution is1.25ml |
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Answer» AnswerCorrect OPTION isA40mln-factor of NAOH = 1n-factor of HCl = 1As we know, N 1 V 1 =N 2 V 2 (0.1×1)(.02)=(.05×1)×V 2 V 2 =0.04 litreV 2 =40ML |
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