The volume of 0.1M Ca(OH)_(2) required to neutralize 10 mL of 0.1 N HC – InterviewSolution

InterviewSolution

1.	The volume of 0.1M Ca(OH)_(2) required to neutralize 10 mL of 0.1 N HCl
Answer» 10 mL 20 mL 5 mL 15 mL Solution :`becauseN=MxxZ` `=0.1xx2=0.2` for `Ca(OH)_(2)` `becauseN_(1)V_(1)=N_(2)V_(2)` `therefore0.2xxV_(1)=0.1xx10` `therefore V_(1)=(0.1xx10)/(0.2)=5ml`

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