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The volume of `10 "moles"` of an ideal gas at `10 atm` and `500 K` isA. `82 L`B. `41 L`C. `20.5 L`D. `(82)/(3)L` |
Answer» Correct Answer - B `n= 10 mol e` `P=10 atm` `T= 500K` `R= 0.0821 L- atm K^(-1)mol^(-1)` `PV= nRT` `10xxV= 10xx0.082xx500` `V= 41L` |
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