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The volume of `10 "moles"` of an ideal gas at `10 atm` and `500 K` isA. `82 L`B. `41 L`C. `20.5 L`D. `(82)/(3)L`

Answer» Correct Answer - B
`n= 10 mol e`
`P=10 atm`
`T= 500K`
`R= 0.0821 L- atm K^(-1)mol^(-1)`
`PV= nRT`
`10xxV= 10xx0.082xx500`
`V= 41L`


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