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The volume of 10 N and 4 N HCl required to make 1L of 6N HCl are : |
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Answer» 0.75 L of 10 N HCl and 0.25 L of 4 N HCl Volume of 4N HCl needed `=1-x` Now `10xx x +4(1-x)=6xx1` `10x+4-4x=6` `6x=2 " or " x=2//6=0.33L` Volume of 10N HCl `=0.33L` Volume of 4N HCl `=1-0.33=0.67L` |
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