1.

The volume of `10` volume of `H_2O_2` required to liberate `500mL` of `O_2` at `STP isA. `25 mL`B. `50 mL`C. `100 mL`D. `125 mL`

Answer» Correct Answer - B
`10` volume `H_(2)O_(2)` means 10 mL of `O_(2)` is produced at `STP` from `1` mL of 10vol `H_(2)O_(2)`
Hence `500` mL of `O_(2)` is produce at `STP` from
`500/10=50` mL of 10 vol `H_(2)O_(2)`


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