1.

The volume of a concentrated H_(2)SO_(4), mixed with 0.5 N KOH to prepare 150 cm^(3) of 0.2 N KOH. Solution is :

Answer»

`50 cm^(3)`
`60 cm^(3)`
`70 cm^(3)`
`80 cm^(3)`

SOLUTION :N//A


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