The volume of a gas expands by 0.25 m^(3) at a constant pressure of 10^(3) N/m, the workdone is equal to .........

The volume of a gas expands by 0.25 m^(3) at a constant pressure of 10

1.	The volume of a gas expands by 0.25 m^(3) at a constant pressure of 10^(3) N/m, the workdone is equal to .........
Answer» 250 W 2.5 W 250 N 250 J Solution :WORKDONE = P. `DELTA V = 10^(3) xx 0.25 = 250 J`