1.

The volume of a gas X and chlorine diffusing during the same time are 35 mL and 29 mL respectively. If molecular mass of chlorine is 71, calculate the molecular mass of gas X.

Answer»

Solution :SUPPOSE the molecular weight of the gas X is `M_1` . ACCORDING to Eq. 5.25, we have
`V_1/V_2 =sqrt(M_2/M_1) ""(t_2and t_2` being the same)
In the present CASE,
`V_1 = 35 mL, V_2 = 29 mL, M_1 = ? " and " M_2 = 71`
`:.35/29 sqrt(71/M_1) " or" M_1 = 48.74`
`:.`The Molecular weight of the gas `X =48.74`.


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