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The volume of a right circular cylinder whose height is 40 cm and the circumference of its base is 66 cm is(a) 55440 cm3 (b) 34650 cm3 (c) 7720 cm3 (d) 13860 cm3 |
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Answer» (d) 13860 cm3 Given, 2πr = 66 ⇒ r = \(\frac{66\times7}{2\times22}= \frac{21}{2}\) cm ∴ V = πr2h = \(\frac{22}{7}\times\frac{22}{7}\times\frac{22}{7}\times40\) = 13860 cm3. |
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