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The volume of air `(O_(2) = 20%)` necessary for the complete combustion of 20 L of propane is :-A. 500 LB. 60 LC. 80 LD. 100 L |
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Answer» Correct Answer - A `underset(20L)(C_(3)H_(8))+underset(100L)(5O_(2))to underset(0)(3CO_(2))+underset(0)(4H_(2)O)` `100 LO=(20)/(100)xxV_("air")` `500=V_("air")` |
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