The volume of CO_(2) liberated at S.T.P and the quantity of heat energy liberated from the combustion of 2.3 g of ethyl alcohol are C_(2)H_(5)OH(l) +3O_(2)(g) rarr 2CO_(2)(g)+3H_(2)O(l) +1367.2

The volume of CO_(2) liberated at S.T.P and the quantity of heat energ

1.	The volume of CO_(2) liberated at S.T.P and the quantity of heat energy liberated from the combustion of 2.3 g of ethyl alcohol are C_(2)H_(5)OH(l) +3O_(2)(g) rarr 2CO_(2)(g)+3H_(2)O(l) +1367.2
Answer» Solution :MOLECULAR weight of `C_(2)H_(5)OH = 46` 46 grams of `C_(2)H_(5)OH` on combustion liberate `2 XX 22.4` lit of `CO_(2)` at S.T.P. and 1367.2 of energy. Volume of `CO_(2)`liberated by the combustion of 2.3 g. of `C_(2)H_(5)OH` `(2.3)/(46) xx 2 xx 22.4 = 2.24` lit Energy liberated by the combustion of 2.3 g `C_(2)H_(5)OH = (2.3)/(46) xx 1367.2 = 68.36 k.j`