The volume of CO, at STP obtained by heating1 gm of CaCO, will be(AIPM

1.	The volume of CO, at STP obtained by heating1 gm of CaCO, will be(AIPMT-91](1) 1 litre(2) 22.4 litres(3) 0.224 litre(4) 11.2 litre52
Answer» Answer: (3) 0.244 litre Explanation: 1 gram of CaCO3 INDICATES 0.01 moles of it. CaCO3 ------------------> CAO + CO2 1mole of CaCO3 gives 1mole of CO2 on heating. so, 0.01 moles of CaCO3 gives 0.01moles of CO2. 1mole of CO2 means 22.4litres of it, thus 0.01 moles of CO2 indicates 0.224litres = 224millilitres please MARK as brainliest

The volume of CO, at STP obtained by heating1 gm of CaCO, will be(AIPMT-91](1) 1 litre(2) 22.4 litres(3) 0.224 litre(4) 11.2 litre52

Answer»

Answer:

(3) 0.244 litre

Explanation:

1 gram of CaCO3 INDICATES 0.01 moles of it.

CaCO3 ------------------> CAO + CO2

1mole of CaCO3 gives 1mole of CO2 on heating.

so, 0.01 moles of CaCO3 gives 0.01moles of CO2.

1mole of CO2 means 22.4litres of it,

thus 0.01 moles of CO2 indicates 0.224litres = 224millilitres

please MARK as brainliest