1.

The volume of ethyl alcohol (density 1.15 g/cc) that has to be added to prepare 100 cc of 0.5 M ethyl alcohol solution in water is

Answer»

1.15 CC
2 cc
2.15 cc
2.30 cc

Solution :100 cc of 0.5 M ethyl alcohol
`-= 100 XX 0.5 xx 10^(-3)` mole `=5 xx 10^(-2)` mole
`therefore` Weight of ethyl alcohol required
`=5 xx 10^(-2) xx 46 g = 2.3 g` [`therefore` Molecular weight of ethyl alcohol = 46]
`therefore d=("Mass")/("VOLUME") RARR 1.15 = 2.3/V rArr V = 2.30/1.15` =2
`therefore` Volume required=2cc


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