The volume of gases evolved at `STP` by passing `0.1A` of current for `965g`, through an aqueous solution of potassium acetateA. `22.4mL`B. `11.2mL`C. `89.6mL`D. `44.8mL`

The volume of gases evolved at `STP` by passing `0.1A` of current for

1.	The volume of gases evolved at `STP` by passing `0.1A` of current for `965g`, through an aqueous solution of potassium acetateA. `22.4mL`B. `11.2mL`C. `89.6mL`D. `44.8mL`
Answer» Correct Answer - d `CH_(3)COOK rarr CH_(3)OO^(c-)+K^(o+)` At cathode, `H_(2)O` undergoes reduction of give `H_(2)`. `H_(2)O+2e^(-) rarr 2overset(c-)(O)H+H_(2)` `2F-=1 mol of H_(2)` At anode, `2CH_(3)COO^(e)rarrunderset(underset(CH_(3)-CH_(3)+2CO_(2))(darr))(2CHOO^(*)+2e^(-))` `2F-=1 mol of C_(2)H_(6)` and `2 mol of CO_(2)` Total volume at cathode and anode `=4 mol =4xx22.4L` `2F=2xx96500Cimplies4xx22.4L` `0.1xx965Cimplies(4xx22.4xx0.1xx965)/(2xx96500)` `implies0.0448L=44.8 mL`

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The volume of gases evolved at `STP` by passing `0.1A` of current for `965g`, through an aqueous solution of potassium acetateA. `22.4mL`B. `11.2mL`C. `89.6mL`D. `44.8mL`

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