1.

The volume of H_(2)STP required to completely reduce 160 gms of Fe_(2)O_(3) is

Answer»

`3 xx 22.4L`
`2 xx 22.4L`
`22.4L`
`11.2L`

SOLUTION :`Fe_(2)O_(3)+3H_(2) RARR 2Fe +3H_(2)O`


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