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The volume of HCI gas weighing 73 g at STP is |
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Answer» 2.24 x 10-2m3 36.5 g of HCl occupies `2.24 xx 10^(-2) m^(3)` . `:.` 73 g of HCI at STP will occupy `(2.24xx10^(-2))/CANCEL(36.5) xx cancel(73^(2))=4.48xx10^(-2)m^(3)`. |
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