The volume of hydrogen at NTP displaced by that amount of current which displaced 1.08 g of Ag (equivalent weight of Ag=108) will beA. 1120ccB. 11.2ccC. 112ccD. 11200cc.

The volume of hydrogen at NTP displaced by that amount of current whic

1.	The volume of hydrogen at NTP displaced by that amount of current which displaced 1.08 g of Ag (equivalent weight of Ag=108) will beA. 1120ccB. 11.2ccC. 112ccD. 11200cc.
Answer» Correct Answer - A g eq. of hydrogen =g eq. of Ag `(W)/(1)=(1.08)/(108)=0.01g` `2g H_(2)` has volume at N.T.P. =22400cc. 0.01g `H_(2)` has volum e at N.T.P. `=(22400)/(2)xx0.01` =112cc.

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