1.

The volume of NH_(3) obtained by the combination of 10mL of N_(2) and 30 mL of H_(2) is

Answer»

20 mL
40 mL
30 Ml
10 mL

Solution :`N_(2)( g) + 3H_(2)( g) RARR 2NH_(3) ( g)`
`1 VOL"" 3 vol rarr 2 vol`
`10 mL"" 30 mL rarr 20 mL`


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