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The volume of nitrogen gas at 0^(@)C and 1.013 bar required to cover a sample of silica gel with unimolecular layer is 129 cm^(3) g^(–1)of gel. Calculate the surface area per gram of the gel if each nitrogen molecule occupies 16.2 xx 10^(–20) m^(2). |
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Answer» Solution :`568m^(2)G^(-1)` `PV=nRT` `1.013 XX 0.129 = n xx 0.0821 xx 273` `n=0.00583` MOL AREA occupied `=0.00583 xx 6.023 xx 10^(23) xx 16.2 xx 10^(-20)` |
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