1.

The volume of one mole of an ideal gas changes from V to 2V at temperature 300 K. If R is universal gas constant, then work done in this process is

Answer»

300 Rln2
600 Rln2
300 ln2
600 ln2

Solution :Working DONE in an isothermal PROCESS
`W = nRT ln ((V_(2))/(V_(1)))`
Here, `n = 1 mol, T = 300 K, V_(1)V` and `V_(2) = 2V`
`:. W = 1 xx R xx 300 ln ((2V)/(V)) = 300 R ln 2`


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