1.

The volume of oxygen liberated at STP from 15 mL of 20 volume H_(2)O_(2) is

Answer»

100 ML
150 mL
200 mL
300 mL

Solution :1 mL of 20 volume `H_(2)O_(2)` liberates `O_(2)` at STP =20 mL
`THEREFORE ` 15 mL of `H_(2)O_(2)` will liberate `O_(2)` at STP `=15xx20=300 `mL


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